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∫dx/(x²-1)=?

x=sinu dx=cosu du ∫dx/[x√(1-x^2)] =∫cosu du/(si...

解: ∫[(x+1)/(x²-2x+5)]dx =∫[(x-1...

∫lnx/(x²-1)dx =xlnx/(x²-1)-∫[1/...

=∫1/(x+1)(x+2)-1/(x+2)²dx =∫1/(x+1)-1/(x+...

令x = tan z,dx = sec² z dz ∫ 1/(1 + x&...

=1/2∫1/(x²-2x+5)d(x²-2x+5)+2∫1/(...

∫x²/(x²+1)dx =∫ (x²+1-...

∫ xln[(1 + x)/(1 - x)] dx = ∫ ln[(1 + x)/(1 - x)]...

∫(x-1)/(1+2x-x²)dx =-1/2∫(2x-2)/(x&#...

d/dx∫(x²~-1)f(t)dt =f(x²)(x&am...

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